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Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn’t matter what you leave beyond the new length.

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class Solution(object):    def removeElement(self, nums, val):        j=0;count=0        for i in range(len(nums)):            if nums[i]!=val:                nums[j]=nums[i]                j=j+1            else:                count=count+1        for i in range(count):            nums.pop()

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